He he, you have missed the point completely here. There is no wire in the
bulb, it is a filament burning at a very high temperature. It is made of
tungsten I think which doubles it resistivity when the temperature increases
from 700 degrees C to 1200 degrees C. It would suspect that the bulb is
burning in that range. So, when there is more power for the bulb, it will
shine brighter, and the temperature increase, and the resistance increases
and therefore the current increase is limited. By changing the wires, you
lessen the voltage drop over the leads to the bulb, hence more voltage over
the bulb, more voltage equals more power unless the current decreases in the
same degree. My strong belief is that the current will increase as a total
though, pretty sure about it. So, go off and shine your wheels or read a
book or two on electronics before beeing too sarcastic about something you
did not understand the whole picture of.
Claes, a swede in Dublin.
-----Original Message-----
From: Nucci [mailto:nucci@...]
Sent: 24 May 2001 07:00
To: Claes Borovac
Cc: 'rhipkiss@...';
DSN_klr650@yahoogroups.com
Subject: Re: [DSN_klr650] extra lights
Wow, you guys have bashed the electrons on this one! Please let me bore you
until you prefer to shine your wheels for an hour or so. The resistance of
the
lamp, in a DC circuit, remains basically a constant as it is a chunk of
wire.
Two variables are Volts and Current. Volts/Resistance = Current. Current
flows, and Voltage is simply a difference of charge at two different points.
An
increase in current over a fixed resistor(the light) will drop more voltage
at
that load (lamp). More current accross a fixed resistance = more voltage
drop
at that point. Like shoving goats accross the river, the harder you push the
more pile up on one bank waiting to cross. The current is limited by the
wiring
gauge and the voltage at the battery. You can't put more volts on a bulb
than a
battery has, but you could match it. You can pass more current accross the
filament and get it brighter and hotter though. So I say that the increased
current flow via the bigger wires and direct connection, has allowed the
full
voltage of the battery to be dropped on the lamp. I am now going to shine
my
own wheels for two hours as self - punishment.
Nucci
91 KLR650
75 Z1-B
Claes Borovac wrote:
> I'd say you are wrong here. You do consume more current. Simply, the
voltage
> over the bulb increases, which gives a higher current through the bulb.
The
> same current that flows through the bulb flows through the wires, that
goes
> without saying.
>
> The question here is, is a bulb a constant current drain? Or not? I would
> say, more voltage over the bulb, more current.
>
> Claes, a swede in Dublin.
>
> -----Original Message-----
> From: Ron Hipkiss [mailto:rhipkiss@...]
> Sent: 23 May 2001 15:52
> To:
DSN_klr650@yahoogroups.com
> Subject: RE: [DSN_klr650] extra lights
>
> Actually, you aren't consuming any more current than with the stock
> cables/wires. Current is constant in a series circuit like that,
regardless
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